A ball with a mass of $360 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $15 (kg)/s^2$ and was compressed by $4/3 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2018-04-25T05:53:16

The height reached by the ball is $=3.78m$

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The spring constant is $k=15kgs^-2$

The compression of the spring is $x=4/3m$

The potential energy stored in the spring is

$PE=1/2kx^2=1/2*15*(4/3)^2=13.33J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

The acceleration due to gravity is $g=9.8ms^-2$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

Mass of the ball is $m=0.360kg$

$PE_(ball)=13.33=0.360*9.8*h$

$h=13.33*1/(0.360*9.8)$

$=3.78m$

The height reached by the ball is $=3.78m$

A ball with a mass of 360 g360 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 15 (kg)/s^215 (kg)/s^2 and was compressed by 4/3 m4/3 m when the ball was released. How high will the ball go?