A ball with a mass of $400 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $45 (kg)/s^2$ and was compressed by $3/4 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-05-09T10:04:22

The height is $=3.23m$

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The spring constant is $k=45kgs^-2$

The compression is $x=3/4m$

The potential energy in the spring is

$PE=1/2*45*(3/4)^2=405/32J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

$PE_(ball)=405/32=0.4*9.8*h$

$h=405/32*1/(0.4*9.8)$

$=3.23m$

A ball with a mass of 400 g400 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 45 (kg)/s^245 (kg)/s^2 and was compressed by 3/4 m3/4 m when the ball was released. How high will the ball go?