A ball with a mass of $420 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $35 (kg)/s^2$ and was compressed by $5/4 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-09-20T05:04:22

The height is $=6.64m$

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The spring constant is $k=35kgs^-2$

The compression is $x=5/4m$

The potential energy in the spring is

$PE=1/2kx^2=1/2*35*(5/4)^2=27.34375J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

The mass of the ball is $=0.420kg$

$PE_(ball)=24.34375=0.240*9.8*h$

The height is $h=24.34375*1/(0.420*9.8)$

$=6.64m$

A ball with a mass of 420 g420 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 35 (kg)/s^235 (kg)/s^2 and was compressed by 5/4 m5/4 m when the ball was released. How high will the ball go?