A ball with a mass of 420 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 18 (kg)/s^2 and was compressed by 6/5 m when the ball was released. How high will the ball go?

1 Answer
P dilip_k
Apr 16, 2016

~~2.62m

Explanation:

By conservation of mechanical energy
PE of the ball at its maximum height when projected by the spring will be equal to PE of the contracted spring
If h m be the max height attained by the ball then

mgh=1/2xxkxxx^2
where

  • m= mass = 0.42kg
  • g = acceleration due to gravity = 9.8m/s^2
  • h = maximum height =?
  • k = force constant of spring = 18(kg)/s^2
  • x=compression of spring =6/5m=1.2m

h =(kx^2)/(2mg)=(18xx1.2)/(2xx0.42xx9.8)~~2.62m

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