A ball with a mass of $480 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $18 (kg)/s^2$ and was compressed by $4/5 m$ when the ball was released. How high will the ball go?

Question

1422 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-01T09:12:02

The height is $=1.22m$

enter image source here

The spring constant is $k=18kgs^-2$

The compression is $x=4/5m$

The potential energy is

$PE=1/2*18*(4/5)^2=5.76J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

The sacceleration due to gravity is $g=9.8ms^-2$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

Mass of the ball is $m=0.48kg$

$PE_(ball)=5.76=0.48*9.8*h$

$h=5.76*1/(0.48*9.8)$

$=1.22m$

The height is $=1.22m$

A ball with a mass of 480 g480 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 18 (kg)/s^218 (kg)/s^2 and was compressed by 4/5 m4/5 m when the ball was released. How high will the ball go?