A ball with a mass of $480 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $24 (kg)/s^2$ and was compressed by $8/5 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-06-11T07:59:01

The height is $=6.53m$

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The spring constant is $k=24kgs^-2$

The compression is $x=8/5m$

The potential energy in the spring is

$PE=1/2*24*(8/5)^2=30.72J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

$PE_(ball)=30.72=0.48*9.8*h$

$h=30.72*1/(0.48*9.8)$

$=6.53m$

A ball with a mass of 480 g480 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 24 (kg)/s^224 (kg)/s^2 and was compressed by 8/5 m8/5 m when the ball was released. How high will the ball go?