A ball with a mass of $50 g$ $50 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $16 \frac{k g}{s^{2}}$ $16 (kg)/s^2$ and was compressed by $\frac{2}{5} m$ $2/5 m$ when the ball was released. How high will the ball go?

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A ball with a mass of $50 g$ $50 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $16 \frac{k g}{s^{2}}$ $16 (kg)/s^2$ and was compressed by $\frac{2}{5} m$ $2/5 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2018-03-05T18:35:58

2.56 m

Explanation:

Acoording to energy conservation,
$gain in potential energy of the ball = loss of energy stored in the compressed spring$ $"gain in potential energy of the ball"="loss of energy stored in the compressed spring"$
thus,
$\frac{1}{2} \times k \times {(x)}^{2} = m \times g \times h$ $frac{1}2 xx k xx(x)^2= mxxgxxh$
or, $h = \frac{16 \times 4}{25}$ $h=frac{16xx4}25$ {on simplification}
$h$ $h$ comes out to be 2.56 metres

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A ball with a mass of $50 g$ $50 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $16 \frac{k g}{s^{2}}$ $16 (kg)/s^2$ and was compressed by $\frac{2}{5} m$ $2/5 m$ when the ball was released. How high will the ball go?

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Explanation:

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A ball with a mass of 50g50 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 16kgs216 (kg)/s^2 and was compressed by 25m2/5 m when the ball was released. How high will the ball go?

1 Answer

Explanation:

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A ball with a mass of $50 g$ $50 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $16 \frac{k g}{s^{2}}$ $16 (kg)/s^2$ and was compressed by $\frac{2}{5} m$ $2/5 m$ when the ball was released. How high will the ball go?