A ball with a mass of $500 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $16 (kg)/s^2$ and was compressed by $8/3 m$ when the ball was released. How high will the ball go?

Question

1722 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-03T13:43:01

$h=11.6" "meters$

enter image source here

$"The potential energy that is stored at any spring can be calculated using formula:":$
$E_p=1/2*K*Delta x^2$

$E_p:"Potential Energy"$

$"K:Spring Constant"$

$Delta x:"amount of compress or stretch"$

$E_p=1/2*16*(8/3)^2$

$E_p=8*64/9=512/9" "J$

$"while object is rising ,"E_p" turns to the gravitational potential energy "$

$512/9=m*g*h$

$m=500 " "gr=0.5" "kg$

$g=9.81 " "N/(kg)$

$512/9=0.5*9.81*h$

$h=512/(9*0.5*9.81)$

$h=11.6" "meters$

A ball with a mass of 500 g500 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 16 (kg)/s^216 (kg)/s^2 and was compressed by 8/3 m8/3 m when the ball was released. How high will the ball go?