A ball with a mass of $70 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $49 (kg)/s^2$ and was compressed by $7/6 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-11-07T08:41:33

The height is $=48.61m$

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The spring constant is $k=49kgs^-2$

The compression is $x=7/6m$

The potential energy in the spring is

$PE=1/2kx^2=1/2*49*(7/6)^2=33.35J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=(h) m$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

The mass of the ball is $=0.070kg$

The acceleration due to gravity is $g=9.8ms^-2$

$PE_(ball)=33.35=0.070*9.8*h$

The height is $h=33.35*1/(0.070*9.8)$

$=48.61m$

A ball with a mass of 70 g70 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 49 (kg)/s^249 (kg)/s^2 and was compressed by 7/6 m7/6 m when the ball was released. How high will the ball go?