A ball with a mass of $80 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $14 (kg)/s^2$ and was compressed by $1/5 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2016-04-17T06:40:10

$h=0,36" "m$

$E_p:" the potential energy for the compressed spring"$
$k=14(kg)/s^2" spring constant"$
$Delta x=1/5 m$

$E_p=1/2*k*Delta x^2$

$E_p=1/2*14*(1/5)^2$

$E_p=7*1/25$

$E_p=0,28J$

$m=80g=0,08 kg" mass of object"$

g=9,81 N/(kg)

$E_g=m*g*h" the gravitational potential energy"$

$E_g=0,08*9,81*h$

$E_g=0,78*h$

$E_p=E_g$

$0,28=0,78*h$

$h=0,28/0,78$

$h=0,36" "m$

A ball with a mass of 80 g80 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 14 (kg)/s^214 (kg)/s^2 and was compressed by 1/5 m1/5 m when the ball was released. How high will the ball go?