A ball with a mass of $80$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $6$ $kgs^-2$ and was compressed by $4/5$ $m$ when the ball was released. How high will the ball go?

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A ball with a mass of $80$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $6$ $kgs^-2$ and was compressed by $4/5$ $m$ when the ball was released. How high will the ball go?

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Answer 1 · 2016-04-04T09:22:24

The spring potential energy in the spring, $E_(p(s))=1/2kx^2=1/2*6*4/5=2.4$ $J$ , will all be converted into gravitational potential energy when the ball is at its highest point. $E_(p(g))=mgh$ . Rearranging, and expressing the mass in $kg$ : $h=E_(p(g))/(mg)=2.4/(0.080*9.8)=3.06$ $m$

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A ball with a mass of $80$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $6$ $kgs^-2$ and was compressed by $4/5$ $m$ when the ball was released. How high will the ball go?

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A ball with a mass of 8080 gg is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 66 kgs^-2 kgs^-2 and was compressed by 4/54/5 mm when the ball was released. How high will the ball go?

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A ball with a mass of $80$ $g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $6$ $kgs^-2$ and was compressed by $4/5$ $m$ when the ball was released. How high will the ball go?