A ball with a mass of $80 g$ is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of $9 (kg)/s^2$ and was compressed by $4/5 m$ when the ball was released. How high will the ball go?

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Answer 1 · 2017-06-06T12:07:11

The height is $=3.67m$

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The spring constant is $k=9kgs^-2$

The compression is $x=4/5m$

The potentialenergy in the spring is

$PE=1/2*9*(4/5)^2=2.88J$

This potential energy will be converted to kinetic energy when the spring is released and to potential energy of the ball

$KE_(ball)=1/2m u^2$

Let the height of the ball be $=h$

Then ,

The potential energy of the ball is $PE_(ball)=mgh$

$PE_(ball)=2.88=0.08*9.8*h$

$h=2.88*1/(0.08*9.8)$

$=3.67m$

A ball with a mass of 80 g80 g is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of 9 (kg)/s^29 (kg)/s^2 and was compressed by 4/5 m4/5 m when the ball was released. How high will the ball go?