A balloon inﬂated at 250 K has a volume of 4.0 L. What is the new volume at constant pressure if the temperature changes to 500 K?

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A balloon inﬂated at 250 K has a volume of 4.0 L. What is the new volume at constant pressure if the temperature changes to 500 K?

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Answer 1 · 2015-11-12T20:04:14

Charles' law states that at constant pressure, absolute temperature and volume are proportional. Mathematically, $V$ $V$ $\propto$ $prop$ $T$ $T$ . $T$ $T$ , the temperature, is quoted in Kelvins.

Explanation:

Given the proportionality, $\frac{V_{1}}{T_{1}}$ $V_1/T_1$ $=$ $=$ $\frac{V_{2}}{T_{2}}$ $V_2/T_2$ . $V_{2}$ $V_2$ is unknown, but $V_{2}$ $V_2$ $=$ $=$ $\frac{T_{2} \times V_{1}}{T_{1}}$ $(T_2xxV_1)/T_1$

Remember, that this assumes a constant pressure. Charles' law is also the reason that we can fly hot air balloons. The experiment has doubled the temperature, so how will volume evolve? Will it get bigger, smaller, remain the same?

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A balloon inﬂated at 250 K has a volume of 4.0 L. What is the new volume at constant pressure if the temperature changes to 500 K?

1 Answer

Explanation:

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