A balloon is filled with 73 Lof air at 1.3 atm pressure. What pressure is needed to change the volume to 43 L?

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A balloon is filled with 73 Lof air at 1.3 atm pressure. What pressure is needed to change the volume to 43 L?

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Answer 1 · 2017-05-12T05:19:13

We use old Boyle's Law........and get approx. $P_{2} = 2 \cdot a t m$ $P_2=2*atm$ .

Explanation:

For a given quantity of gas, pressure is inversely proportional to pressure: $P \propto \frac{1}{V}$ $Pprop1/V$ . And so $P V = k$ $PV=k$ , and thus $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ .

We solve for $P_{2} = \frac{P_{1} V_{1}}{V_{2}} = \frac{73 \cdot L \times 1.3 \cdot a t m}{43 \cdot L} = ? ? a t m .$ $P_2=(P_1V_1)/(V_2)=(73*Lxx1.3*atm)/(43*L)=??atm.$

Is it reasonable that pressure has increased? Why?

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A balloon is filled with 73 Lof air at 1.3 atm pressure. What pressure is needed to change the volume to 43 L?

1 Answer

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