A balloon with a volume of $2.00L$ is filled with helium gas at a temperature of $27.0˚C$ and a pressure of $1.20 atm$ . How many grams of helium are in the balloon?

Question

18903 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-28T05:19:44

A mass of approx. $0.4*g$ is contained........

Given $n="Mass"/"Molar mass"=(PV)/(RT)$ .

$"Mass"=(PV)/(RT)xx"molar mass"$ ,

.........Agreed........?

And, as is typical, we use the value of..........

$R=0.0821*L*atm*K^-1*mol^-1$

The which has units that chemists typically use. And so we plugs in the numbers:

$"Mass"=(1.2*atmxx2.00*Lxx4.00*g*mol^-1)/(0.0821*(L*atm)/(K*mol)xx300*K)$

$~=400*mg$

A balloon with a volume of 2.00L2.00L is filled with helium gas at a temperature of 27.0˚C27.0˚C and a pressure of 1.20 atm1.20 atm. How many grams of helium are in the balloon?