A body is dropped from a height h under acceleration due to gravity g. if t1 and t2 are the time intervals for its fall for the first one third distance and the rest 2/3 distance, then the relation between t1 and t2 is..??

1 Answer
Apr 9, 2018

#t_2 = (sqrt3 -1)t_1#

Explanation:

Let the distance the particle falls in time #t_1 # be #d#. Then , the distance it travels in time #t_1+t_2# is #3d#.

Thus

#d = 1/2 g t_1^2#
#3d = 1/2 g(t_1+t_2)^2#

Hence

#3 = (t_1+t_2)^2/t_1^2 implies#

#(t_1+t_2)/t_1 = sqrt3 implies #
#t_2/t_1 = sqrt3 -1#