A body with uniform acceleration travel distance 12m in the third second and 20metre in fifth second.find the velocity after 10th second?

1 Answer
Sunayan S
Jun 10, 2017

#42ms^-1#

Explanation:

Here a formula,
#S=u+1/2a(2n-1)# where S is displacement,u= initial velocity
and n=time
#1_(st) case#,
#12=u+(5a)/2##=>24=2u+5a#
Similarly,
#40=2u+9a#
From both equations, #a=4ms^-2#
#u=2ms^-1#
In #10_th# sec the velocity of the body is #u+at#=#2+(4×10)#=#42ms^-1#

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