A body with uniform acceleration travel distance 12m in the third second and 20metre in fifth second.find the velocity after 10th second?

Question

A body with uniform acceleration travel distance 12m in the third second and 20metre in fifth second.find the velocity after 10th second?

1 Answer

Impact of this question

955 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-10T04:44:09

$42 m s^{- 1}$ $42ms^-1$

Explanation:

Here a formula,
$S = u + \frac{1}{2} a (2 n - 1)$ $S=u+1/2a(2n-1)$ where S is displacement,u= initial velocity
and n=time
$1_{s t} c a s e$ $1_(st) case$ ,
$12 = u + \frac{5 a}{2}$ $12=u+(5a)/2$ $\Rightarrow 24 = 2 u + 5 a$ $=>24=2u+5a$
Similarly,
$40 = 2 u + 9 a$ $40=2u+9a$
From both equations, $a = 4 m s^{- 2}$ $a=4ms^-2$
$u = 2 m s^{- 1}$ $u=2ms^-1$
In $10_{t} h$ $10_th$ sec the velocity of the body is $u + a t$ $u+at$ = $2 + (4 \times 10)$ $2+(4×10)$ = $42 m s^{- 1}$ $42ms^-1$

Science

Math

Humanities

... and beyond

A body with uniform acceleration travel distance 12m in the third second and 20metre in fifth second.find the velocity after 10th second?

1 Answer

Explanation:

Related questions

Impact of this question