A car travelling at 60 kmph overtakes another car travelling at 42 kmph. Assuming each car to be 5.0 m long, find the time taken to overtake and the total distance used for overtake.?

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Answer 1 · 2017-11-24T07:15:08

The time taken to overtake is $= 2 s$ $=2s$ . The total distance to overtake is $= 38.33 m$ $=38.33m$

Let the speed of the first car be

$v_{A} = 60 \cdot \frac{1000}{3600} = 16.67 m s^{- 1}$ $v_A=60*1000/3600=16.67ms^-1$

Let the speed of the second car be

$v_{B} = 42 \cdot \frac{1000}{3600} = 11.67 m s^{- 1}$ $v_B=42*1000/3600=11.67ms^-1$

The length of each is $d = 5 m$ $d=5m$

The time taken to overtake is

$t=d/(Deltav)=d/(v_A-v_B)=10/(16.67-11.67)=10/5=2s$

The total distance travelled to overtake is

$s=(3*16.67-11.67)=38.33m$