A charge of $16 C$ $16 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $48 J$ $48 J$ to $12 J$ $12 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-04-14T15:35:39

$V_{AB} = - 2, 25 V$ $V_"AB"=-2,25 V$

$q = 16 C$ $q=16C$
$E_{A} = 48 J the electric potential energy at the point of A$ $E_A=48 J" the electric potential energy at the point of A"$

$E_{B} = 12 J the electric potential energy at the point of B$ $E_B=12J" the electric potential energy at the point of B"$

$E_{B} - E_{A} = 12 - 48 = - 36 J work between the A and B$ $E_B-E_A=12-48=-36J" work between the A and B"$

$W = q \cdot V_{AB}$ $W=q*V_"AB"$

$- 36 = 16 \cdot V_{AB}$ $-36=16*V_"AB"$

$V_{AB} = - \frac{36}{16}$ $V_"AB"=-36/16$

$V_{AB} = - 2, 25 V$ $V_"AB"=-2,25 V$

A charge of 16C16 C is passing through points A and B on a circuit. If the charge's electric potential changes from 48J48 J to 12J12 J, what is the voltage between points A and B?