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A charge of $16 C$ $16 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $28 J$ $28 J$ to $4 J$ $4 J$ , what is the voltage between points A and B?

1 Answer

Feb 15, 2016

V= E / Q. Thus $V = \frac{24 J}{16 C} = 1.5 V$ $V = (24 J) / (16 C) = 1.5 V$

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