A charge of #2 C# is at #(-2 , 4 )# and a charge of #-1 C# is at #(-6 ,8 ) #. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2018-05-24T08:42:35

#5.62*10^8"N"#

#F=(kQ_1Q_2)/r^2#, where:

#r^2=(Deltax)^2+(Deltay)^2=(8-4)^2+(-6+2)^2=4^2+4^2=32#

#F=(2(8.99*10^9))/32=(8.99*10^9)/16=5.62*10^8"N"#