Question

A charge of `2 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `28 J` to `19 J`, what is the voltage between points A and B?

Answer 1

`V_"AB"=-4.5" "V`

Explanation:

`Delta W=19-28=-9J`

`Delta W=q(V_B-V_A)" ; "V_B-V_A=V_"AB"`

`Delta W=q*V_"AB"`

`V_"AB"=(Delta W)/q`

`V_"AB"=-9/2`

`V_"AB"=-4.5" "V`