A charge of $2 C$ $2 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $25 J$ $25 J$ to $14 J$ $14 J$ , what is the voltage between points A and B?

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Answer 1 · 2018-02-13T12:01:31

$5.5 V$ $5.5"V"$

The relationship between the change in electric potential and the voltage and charge between two points is:

$W = q V$ $W=qV$ , where:

$W$ $W$ is the change in potential energy, or the work done.

$q$ $q$ is the charge passing through the points

$V$ $V$ is the difference in voltage.

Rearranging the equation to solve for $V$ $V$ , we get:

$V = \frac{W}{q}$ $V=W/q$ .

Here, $W = 25 J - 14 J = 11 J$ $W=25"J"-14"J"=11"J"$ , and $q = 2 C$ $q=2"C"$ .

Inputting these values, we get:

$V = \frac{11}{2}$ $V=11/2$

$V = 5.5$ $V=5.5$ volts.

A charge of 2 C2C2 C is passing through points A and B on a circuit. If the charge's electric potential changes from 25 J25J25 J to 14 J14J14 J, what is the voltage between points A and B?