Question

A charge of `3 C` is at `(9 , 3 )` and a charge of `-1 C` is at `(-2 , 4 )`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F_(AB)~=-0,22*10^9`

Explanation:

`"distance between the Point A and B :"`
`AB=sqrt (11^2+1^2)=sqrt (121+1)=sqrt 122" unit"`
`"Force between two charges is given :"`
`F_(AB)=-F_(BA)=(k*q_1*q_2)/d^2`
`F_(AB)=(9*10^9*(-1)*3)/122`
`F_(AB)=-(27*10^9)/122`
`F_(AB)~=-0,22*10^9`