A charge of 5 C5C is passing through points A and B on a circuit. If the charge's electric potential changes from 32 J32J to 18 J18J, what is the voltage between points A and B?

1 Answer
Apr 23, 2016

V_"AB"=-2,8VVAB=2,8V

Explanation:

"Voltage between two points is given by " V_"AB"=W_"AB"/qVoltage between two points is given by VAB=WABq
"where "W_"AB": "work done between A and B ; q:charge"where WAB:work done between A and B ; q:charge

W_"AB"=18-32=-14JWAB=1832=14J
q=5Cq=5C

V_"AB"=-14/5VAB=145

V_"AB"=-2,8VVAB=2,8V