A charge of $8 C$ $8 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $36 J$ $36 J$ to $6 J$ $6 J$ , what is the voltage between points A and B?

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Answer 1 · 2018-02-25T16:29:47

Voltage difference = the change in potential energy/charge

So, we can say as potential energy of charge at $A$ $A$ is higher than that at $B$ $B$ , $A$ $A$ is at higher voltage than $B$ $B$ ,

So,the Voltage difference between them is $\frac{36 - 6}{8} = 3.75 V$ $(36-6)/8 =3.75 V$

Answer 2 · 2018-02-25T16:31:01

The voltage between A and B is 4V (1s.f.)

The change in energy is $30 J$ $30J$ and the charge is $8 C$ $8C$

Using the formula $E = Q V$ $E=QV$ , since voltage is simply the energy gained/lost per coulomb of charge,

$V = \frac{30}{8} = 3.75 V$ $V= 30/8 = 3.75V$

A charge of 8C8 C is passing through points A and B on a circuit. If the charge's electric potential changes from 36J36 J to 6J6 J, what is the voltage between points A and B?