Question

A charge of `8 C` is passing through points A and B on a circuit. If the charge's electric potential changes from `34 J` to `12 J`, what is the voltage between points A and B?

Answer 1

`V_"AB"=-11/4 V`

Explanation:

`Delta P=q*Delta V`

`Delta V=V_B-V_A=V_"AB"`

`Delta P=12-34=-22J`

`-22=8*V_"AB"`

`V_"AB"=-22/8`

`V_"AB"=-11/4 V`