A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $9 J$ $9 J$ to $3 J$ $3 J$ , what is the voltage between points A and B?

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A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $9 J$ $9 J$ to $3 J$ $3 J$ , what is the voltage between points A and B?

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Answer 1 · 2016-04-12T06:20:30

$V_{AB} = - \frac{2}{3} V$ $V_"AB"=-2/3 V$

Explanation:

$data:$ $"data:"$
$q = 9 C$ $q=9C$
$E_{A} = 9 J potential energy for the point of A$ $E_A=9J" potential energy for the point of A"$
$E_{B} = 3 J potential energy for the point of B$ $E_B=3J" potential energy for the point of B"$

$W=Delta E=E_B-E_A" work doing between two point"$

$W=3-9=-6J$

$W=q(V_B-V_A)$

$V_"AB"=V_B-V_A$

$W=q*V_"AB"$

$-6=9*V_"AB"$

$V_"AB"=-2/3 V$

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A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $9 J$ $9 J$ to $3 J$ $3 J$ , what is the voltage between points A and B?

1 Answer

Explanation:

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A charge of $9 C$ $9 C$ is passing through points A and B on a circuit. If the charge's electric potential changes from $9 J$ $9 J$ to $3 J$ $3 J$ , what is the voltage between points A and B?