A chemist obtains 2.50 moles of sodium nitrate ( $N a N O_{3}$ $NaNO_3$ ). What is the mass of this sample?

Question

The molar masses for the elements are Na = 23.0 g, N = 14.0 g, and O = 16.0 g.

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Answer 1 · 2017-03-26T01:22:22

Very simple. Follow below.

You are given $2.50 moles$ $"2.50 moles"$ of sodium nitrate, $(N a N O 3)$ $(NaNO3)$ .

Given moles, now, you are to convert back to mass (in grams).

To do this, you need to set up the problem as follows:

First, find the formula mass of the compound using the periodic table.

$N a = 23 g$ $Na = 23 g$
$N = 14 g$ $N = 14 g$
$O = 16 g \cdot 3 = 48 g$ $O = 16g * 3 = 48 g$

Total = 85 grams

So, for every $1 mole$ $1 "mole"$ of $N a N O_{3}$ $NaNO_3$ , you have 85 grams.

We will set up a conversion factor to solve for mass in grams of the sample using moles of $N a N O_{3}$ $NaNO_3$ .

$(2.50 cancel"moles")/1 * (85color(white)(.)"grams")/(1 cancel"mole") = "212.5 grams"$

Answer: 212.5 grams of $NaNO_3$