A circuit with a resistance of #6 Omega# has a fuse with a capacity of #5 A#. Can a voltage of #32 V# be applied to the circuit without blowing the fuse?
1 Answer
Apr 6, 2016
Current I = E/R where I=current E voltage R resistance.
Explanation:
Current 32/6=5.33 amps.Fuse is designed to blow at 5 amps.So it will blow out at this Resistance
Should not be applied..
