A circuit with a resistance of #8 Omega# has a fuse with a capacity of #3 A#. Can a voltage of #36 V# be applied to the circuit without blowing the fuse?

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Answer 1 · 2018-05-25T00:24:57

No.

Well, we need to find the voltage that the fuse can hold, so we use Ohm's law, which states that,

#V=IR#

where:

#V# is the voltage in volts

#I# is the current in amperes

#R# is the resistance in ohms

So, we get:

#V=3 \ "A"*8 \ Omega#

#=24 \ "V"#

Since a voltage of #36# volts is applied to the circuit, but the fuse only holds #24# volts, it'll blow up the fuse.