A closed food jar has a fixed volume at STP. What would the new pressure be at 45°C?
1 Answer
Explanation:
Recall that Gay-Lussac's Law states that pressure is directly proportional to temperature , as long as the volume and number of moles of the gas remain constant.
Gay-Lussac's Law can be expressed mathematically with the formula,
color(blue)(|bar(ul(color(white)(a/a)P_1/T_1=P_2/T_2color(white)(a/a)|))) where:
P_1= initial pressure
T_1= inital temperature (Kelvin)
P_2= final pressure
T_2= final temperature (Kelvin)
Determining the Final Pressure
STP conditions (initial):
initial pressurecolor(orange)((P_1)) :color(orange)(101.325kPa)
initial temperaturecolor(purple)((T_1)) :color(purple)(273.15K) New conditions (final)
final pressurecolor(teal)((P_2)) :color(teal)(P_2)
final temperaturecolor(magenta)((T_2)) :45^@C+273.15=color(magenta)(318.15K)
color(orange)(P_1)/color(purple)(T_1)=color(teal)(P_2)/color(magenta)(T_2)
color(teal)(P_2)=(color(magenta)(T_2))((color(orange)(P_1))/(color(purple)(T_1)))
color(teal)(P_2)=(color(magenta)(318.15K))(color(orange)(101.325kPa)/color(purple)(273.15K))
color(teal)(P_2)=(color(magenta)(318.15color(red)cancelcolor(magenta)K))(color(orange)(101.325kPa)/color(purple)(273.15color(red)cancelcolor(purple)K))
color(teal)(P_2)=118.0177512kPa
color(teal)(P_2)~~color(green)(|bar(ul(color(white)(a/a)318kPacolor(white)(a/a)|)))