A compound contains 1.10 mol of K, 055 mol of Te, and 1.65 mol O. What is the simplest formula of this compound?

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A compound contains 1.10 mol of K, 055 mol of Te, and 1.65 mol O. What is the simplest formula of this compound?

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Answer 1 · 2016-12-15T08:19:12

If we assume you meant $0.55 \cdot m o l$ $0.55*mol$ $tellurium$ $"tellurium"$ , we get an $empirical formula$ $"empirical formula"$ of $K_{2} T e O_{3}$ $K_2TeO_3$ .

Explanation:

We divide thru by the SMALLEST molar quantity, that of tellurium, to get an empirical formula.

$Moles of tellurium$ $"Moles of tellurium"$ $=$ $=$ $\frac{0.55 \cdot m o l}{0.55 \cdot m o l} = 1$ $(0.55*mol)/(0.55*mol)=1$

$Moles of potassium$ $"Moles of potassium"$ $=$ $=$ $\frac{1.10 \cdot m o l}{0.55 \cdot m o l} = 2$ $(1.10*mol)/(0.55*mol)=2$

$Moles of oxygen$ $"Moles of oxygen"$ $=$ $=$ $\frac{1.65 \cdot m o l}{0.55 \cdot m o l} = 3$ $(1.65*mol)/(0.55*mol)=3$

And thus the empirical formula is $K_{2} T e O_{3}$ $K_2TeO_3$ .

All I have done is to divide thru by the SMALLEST MOLAR QUANTITY.

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A compound contains 1.10 mol of K, 055 mol of Te, and 1.65 mol O. What is the simplest formula of this compound?

1 Answer

Explanation:

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