Question

A compound has a molecular mass of 54 and an empirical formula of `C_2H_3`. What is the molecular formula of the compound?

Answer 1

proceed as follows

Explanation:

let the MF be`(C_2H_3)n`
using atomic mass of C =12
and of hydrogen H =1
the calculated Molar mass becomes (2x12+3x1)n =27n
so 27n = 54
hen n =2
So MF Will be `C_4H_6`