A compound with empirical formula CH was found by experiment to have a molar mass of approximately 91. What is the molecular formula of the compound?

1 Answer
anor277
Nov 9, 2015

The molecular formula is always a multiple of the empirical formula.

Explanation:

So, MF = n*(EF), where MF, EF are the molecular and empirical formulae respectively.

Thus, 91*g*mol^-1= nxx(12 + 1)*g*mol^-1.

Or n=91/13; so n = 7? Please report the molecular formula back here.

Related questions
See all questions in Empirical and Molecular Formulas
Impact of this question
4300 views around the world
You can reuse this answer
Creative Commons License