A compounds empirical formula is HO. If the formula mass is 34 amu, what is the molecular formula?

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A compounds empirical formula is HO. If the formula mass is 34 amu, what is the molecular formula?

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Answer 1 · 2016-11-23T16:25:58

$Molecular formula$ $"Molecular formula"$ $=$ $=$ $H_{2} O_{2}$ $H_2O_2$ .

Explanation:

The molecular formula is always a whole number mulitple of the empirical formula, and of course the multiple might be $1$ $1$ .

So here, $(Molecular formula)$ $("Molecular formula")$ $=$ $=$ $(Empirical formula \times n)$ $("Empirical formula" xx n)$

And thus,

$(Molecular mass) = 34 \cdot g \cdot m o l^{- 1} = n \times (1.008 + 15.999) \cdot g \cdot m o l^{- 1}$ $("Molecular mass")=34*g*mol^-1=nxx(1.008+15.999)*g*mol^-1$

Clearly $n = 2$ $n=2$ , and the molecular formula of hydrogen peroxide is $H_{2} O_{2}$ $H_2O_2$ .

What is the oxidation number of oxygen in this molecule?

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A compounds empirical formula is HO. If the formula mass is 34 amu, what is the molecular formula?

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