A crate with a mass of 12kg is sliding across the floor with a velocity of 8.8m/s. If the coefficient of kinetic friction is 0.16, how far will it slide before coming to rest?

please show all of your work

1 Answer
Sep 22, 2016

Given

#v->"Velocity of the crate"=8.8"m/s"#

#m->"Mass of the crate"=12kg#

#mu->"Coefficient of kinetic frixtion"=0.16#

#"Let the crate slides x m before coming to rest"#

By consudering conservation of energy we can write

#mumgx=1/2mv^2#

#=>x=v^2/(2mug)=8.8^2/(2xx0.16xx9.8)m~~24.7m#