A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15°C. How many gas particles are in this bubble?

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A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15°C. How many gas particles are in this bubble?

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Answer 1 · 2016-06-02T18:13:20

Approx. $0.025 \times N_{A}, N_{A} = Avogadro's Number$ $0.025xxN_A, N_A="Avogadro's Number"$

Explanation:

$n = \frac{P V}{R T} = \frac{2.4 \cdot a t m \times 0.250 \cdot L}{0.0821 \cdot L \cdot a t m \cdot K^{- 1} m o l^{- 1} \times 288 \cdot K} = 0.0254 \cdot m o l$ $n=(PV)/(RT)=(2.4*atmxx0.250*L)/(0.0821*L*atm*K^-1mol^-1xx288*K)=0.0254*mol$

What sort of gas would be in the bubble? Would this be the same as the gas in the gas bottle?

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A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15°C. How many gas particles are in this bubble?

1 Answer

Explanation:

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