A father left all of his money to his 3 children. Child A received 1/6 of his father's money while Child B received 1/7. Child C, who received the remainder of the money , was given $23,490. How much did Child A receive?

1 Answer
Oct 18, 2017

See a solution process below:

Explanation:

First, we need to determine what "slice" of the money Child C received:

Let's call the "slice" Child C received: cc

100% is the same as 1 so we can write and solve this equation for cc;

1/6 + 1/7 + c = 116+17+c=1

(7/7 xx 1/6) + (6/6 xx 1/7) + c = 1(77×16)+(66×17)+c=1

7/42 + 6/42 + c = 1742+642+c=1

(7 + 6)/42 + c = 17+642+c=1

13/42 + c = 11342+c=1

13/42 - color(red)(13/42) + c = 1 - color(red)(13/42)13421342+c=11342

0 + c = 42/42 - color(red)(13/42)0+c=42421342

c = (42 - color(red)(13))/42c=421342

c = 29/42c=2942

Child C received 29/422942 of his father's money.

Now, let's call the total amount of money the father left for the 3 children: aa

We can write this equation and solve for aa:

29/42 xx a = $234902942×a=$23490

color(red)(42)/color(blue)(29) xx 29/42 xx a = color(red)(42)/color(blue)(29) xx $234904229×2942×a=4229×$23490

cancel(color(red)(42))/cancel(color(blue)(29)) xx color(blue)(cancel(color(black)(29)))/color(red)(cancel(color(black)(42))) xx a = color(red)(42)/color(blue)(29) xx ($810 xx 29)

a = color(red)(42)/cancel(color(blue)(29)) xx ($810 xx color(red)(cancel(color(black)(29))))

a = color(red)(42) xx $810

a = $34020

We now know the total amount of money the father left to all the children was $34,020.

Child A received 1/6 of this money:

1/6 xx $34020 =>

1/6 xx $5670 xx 6 =>

1/color(red)(cancel(color(black)(6))) xx $5670 xx color(red)(cancel(color(black)(6))) =>

$5670

Child A received $5,670