A flask contains three times as many moles as H_2H2 as it does O_2O2 gas. If hydrogen and oxygen are the only present gases, what is the total pressure flask if the partial pressure due to oxygen is PP?
1 Answer
Explanation:
According to Dalton's Law of Partial Pressures, the total pressure of a gaseous mixture will be equal to the individual partial pressure of each component of the mixture.
Simply put, to get the total pressure of a gaseous mixture, you add up the partial pressure you'd get for each component of that mixture if it occupied the volume of the mixture alone.
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Mathematically, this can written as
color(blue)(|bar(ul(color(white)(a/a)P_"total" = sum_i P_icolor(white)(a/a)|)))" " , where
In your case, the mixture is said to contain hydrogen gas,
This means that if you take
n_(H_2) = 3 xx n_(O_2)" "color(purple)("(*)")
Now, let's assume that the mixture is being held in a container that has a volume of
color(blue)(|bar(ul(color(white)(a/a)PV = nRT color(white)(a/a)|)))
to express
P * V = n_(O_2) * RT implies V = n_(O_2)/P * RT" "color(red)("(*)")
Now, you can write the same thing for
P^' * V = n_(H_2) * RT implies V = n_(H_2)/P^' * RT
Use equation
n_(O_2)/P * color(red)(cancel(color(black)(RT))) = n_(H_2)/P^' * color(red)(cancel(color(black)(RT)))
Rearrange to find
P^' = n_(H_2)/n_(O_2) * P
Use equation
P^' = (3 xx color(red)(cancel(color(black)(n_(O_2)))))/color(red)(cancel(color(black)(n_(O_2)))) * P
P^' = 3 xx P
Finally, plug this into the equation that describes Dalton's Law of Partial Pressures to get the total pressure of the mixture,
P_"total" = P^' + P
P_"total" = 3 xx P + P = color(green)(|bar(ul(color(white)(a/a)4 xx Pcolor(white)(a/a)|)))