A gas a volume of 2.50 L at a pressure of of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?

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A gas a volume of 2.50 L at a pressure of of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?

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Answer 1 · 2016-05-02T18:56:04

The new volume of the gas is $0.500 L$ $"0.500 L"$ .

Explanation:

This is an example of Boyle's law, which states that at constant temperature and mass, the volume of a gas will vary inversely with the pressure. The equation to use for solving your question is $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ , where $P_{1}$ $P_1$ is initial pressure, $V_{1}$ $V_1$ is initial volume, $P_{2}$ $P_2$ is the final pressure, and $V$ $V$ is the final volume.

Known
$P_{1} = 350.0 kPa$ $P_1="350.0 kPa"$
$V_{1} = 2.50 L$ $V_1="2.50 L"$
$P_{2} = 1750 kPa$ $P_2="1750 kPa"$

Unknown
$V_{2} = ???$ $V_2="???"$

Solution
Rearrange the equation to isolate $V_{2}$ $V_2$ . Substitute the known values into the equation and solve.

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

$V_{2} = \frac{P_{1} V_{1}}{P_{2}}$ $V_2=(P_1V_1)/P_2$

$V_2=(350.0cancel"kPa"xx2.50"L")/(1750 cancel"kPa")="0.500 L"$

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A gas a volume of 2.50 L at a pressure of of 350.0 kPa. If the temperature remains constant, what volume would the gas occupy at 1750 kPa?

1 Answer

Explanation:

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