A gas at 155 kPa and 25°C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

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Answer 1 · 2017-11-21T03:04:45

#"0.34 L"#

Ideal gas equation is

#PV = nRT#

#(PV)/T = nR#

In both the cases #(PV)/T# is equal to #nR#

Therefore,

#(P_1V_1)/T_1 = (P_2V_2)/T_2#

#V_2 = (P_1V_1)/T_1 × T_2/P_2#

#V_2 = (155 cancel"kPa" × "1.00 L")/(298 cancel"K") × (398 cancel"K")/(605 cancel"kPa") = "0.34 L"#