A gas at 155 kPa and 25'C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

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Answer 1 · 2018-01-21T13:26:38

#V_2=0.342*L#...the gas is compressed....

We use the old #"combined gas law..."#

#(P_1V_1)/T_1=(P_2V_2)/T_2#

And if we solve for #V_2=(P_1V_1)/T_1xxT_2/P_2#...the which product CLEARLY has the units of #"volume"#. And we plug in the values....

#V_2=(155*cancel(kPa)xx1.00*Lxx398*cancelK)/(298*cancelKxx605*cancel(kPa))=0.342*L#

Pressure wins here over temperature....