A gas at 155 kPa and 25'C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

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A gas at 155 kPa and 25'C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

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Answer 1 · 2018-01-21T13:26:38

$V_{2} = 0.342 \cdot L$ $V_2=0.342*L$ ...the gas is compressed....

Explanation:

We use the old $combined gas law...$ $"combined gas law..."$

$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ $(P_1V_1)/T_1=(P_2V_2)/T_2$

And if we solve for $V_{2} = \frac{P_{1} V_{1}}{T_{1}} \times \frac{T_{2}}{P_{2}}$ $V_2=(P_1V_1)/T_1xxT_2/P_2$ ...the which product CLEARLY has the units of $volume$ $"volume"$ . And we plug in the values....

$V_2=(155*cancel(kPa)xx1.00*Lxx398*cancelK)/(298*cancelKxx605*cancel(kPa))=0.342*L$

Pressure wins here over temperature....

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A gas at 155 kPa and 25'C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

1 Answer

Explanation:

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