A gas at pressure of 5.0 bar from 0 to 546°c and simultaneously compressed to one third of its original volume.What will be the final pressure in bar?

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A gas at pressure of 5.0 bar from 0 to 546°c and simultaneously compressed to one third of its original volume.What will be the final pressure in bar?

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Answer 1 · 2016-10-01T08:29:23

Final pressure =5 bar

Explanation:

$Initial Pressure of the gas = P_{1} = 5 bar$ $"Initial Pressure of the gas"=P_1=5" bar"$

$Initial Volume of the gas = V_{1} L$ $"Initial Volume of the gas"=V_1 L$

$Initial Temperature of the gas = T_{1} = (0 + 273) K = 273 K$ $"Initial Temperature of the gas"=T_1=(0+273)K=273K$

$Final pressure of the gas = P_{2} = ?$ $"Final pressure of the gas"=P_2=?$

$Final Volume of the gas = V_{2} L$ $"Final Volume of the gas"=V_2 L$

$Final Temperature of the gas = T_{2} = (546 + 273) K = 819 K$ $"Final Temperature of the gas"=T_2=(546+273)K=819K$

Given condition is the is compressed to one third of its original volume.

So $V_{1} = 3 V_{2}$ $V_1=3V_2$

We know from gas law

$\frac{P_{2} V_{2}}{T_{2}} = \frac{P_{1} V_{1}}{T_{1}}$ $(P_2V_2)/T_2=(P_1V_1)/T_1$

$\frac{P_{2} V_{2}}{819} = \frac{5 \times 3 V_{2}}{273}$ $(P_2V_2)/819=(5xx3V_2)/273$

$P_2=(5xx3xxcancel819^3)/cancel273" bar"=45" bar"$

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A gas at pressure of 5.0 bar from 0 to 546°c and simultaneously compressed to one third of its original volume.What will be the final pressure in bar?

1 Answer

Explanation:

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