Question

A gas has a volume of 2000 mL at -253 °C and a pressure of 101.3 kPa. What will be the new volume when the temperature is changed to -233 °C and the pressure is changed to 198.5 kPa?

Answer 1

`(P_1V_1)/T_1=(P_2V_2)/T_2`, #V_2 ~=2.5*L#

Explanation:

We use `"degrees Kelvin"`, and so `V_2=(P_1*V_1*T_2)/(P_2*T_1)`

`=(101.3*kPaxx2000*mLxx50*K)/(198.5*kPaxx20*K)`

`=??mL`