A gas has a volume of 2000 mL at -253 °C and a pressure of 101.3 kPa. What will be the new volume when the temperature is changed to -233 °C and the pressure is changed to 198.5 kPa?

1 Answer
May 11, 2017

(P_1V_1)/T_1=(P_2V_2)/T_2P1V1T1=P2V2T2, V_2 ~=2.5*LV22.5L

Explanation:

We use "degrees Kelvin"degrees Kelvin, and so V_2=(P_1*V_1*T_2)/(P_2*T_1)V2=P1V1T2P2T1

=(101.3*kPaxx2000*mLxx50*K)/(198.5*kPaxx20*K)=101.3kPa×2000mL×50K198.5kPa×20K

=??mL=??mL