A gas occupies 1.58 liters its pressure is 5.2 atm and its temperature is 57.4°C. What would volume be if the pressure were decreased to 3.59 atm?

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A gas occupies 1.58 liters its pressure is 5.2 atm and its temperature is 57.4°C. What would volume be if the pressure were decreased to 3.59 atm?

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Answer 1 · 2016-10-01T15:53:29

At constant $T$ $T$ , pressure is inversely proportional to volume: this is [Boyle's law.](https://en.wikipedia.org/wiki/Boyle%27s_law)

Explanation:

Given $P \propto \frac{1}{V}$ $Pprop1/V$ , $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ , and the great advantage of this proportionality is that we can use unorthodox units of pressure and volume, i.e. $psi, pints, atmosphere, gallons$ $"psi, pints, atmosphere, gallons"$ so long as we are consistent.

We want $V_{2}$ $V_2$ $=$ $=$ $\frac{P_{1} V_{1}}{P_{2}}$ $(P_1V_1)/P_2$ $=$ $=$ $(5.2*cancel(atm)xx1.58*L)/(3.59*cancel(atm))$ $~=$ $2*L?$

Note that the volume has INCREASED, as we would anticipate upon reduction of pressure.

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A gas occupies 1.58 liters its pressure is 5.2 atm and its temperature is 57.4°C. What would volume be if the pressure were decreased to 3.59 atm?

1 Answer

Explanation:

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