Question

A gas occupies 11.2 liters at 0.860 atm. What is the pressure if the volume becomes 15.0 L?

Answer 1

Boyle studied the relationship between the pressure of a trapped gas and its volume. The data obtained by him shows that the product of pressure and volume for the trapped air sample is constant at a constant temperature.

if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is `V_1` and its pressure is `P_1`. Let us suppose that its volume has been increased to `V_2`, the as per the Boyle's law its pressure will decrease and let us assume the new pressure is `P_2`.

`P_1` `V_1` =`P_2` `V_2`

`P_1` = 0.860 atm
`V_1` = 11.2 L
`P_2` = ?
`V_2`= 15 L substitute the values;

0.860 atm x 11.2 L = `P_2` x 15 L

`P_2` = 0.860 atm x 11.2 L / 15 L

`P_2` = 9.632 atm L / 15 L = 0.642 atm