A gas occupies 12.3 at a pressure of 40.0 KPa. What is the volume when the pressure is increased to 60.0 KPa?

1 Answer

The volume is =8.2u, whatever the chosen units were to begin with...

Explanation:

We apply Boyle's Law at constant temperature and constant number of mols:

P1V1=P2V2

The initial pressure is P1=40kPa

The initial volume is V1=12.3

The final pressure is 60kPa

The final volume is

V2=P1P2V1

=406012.3=8.2u