A gas occupies 12.3 at a pressure of 40.0 KPa. What is the volume when the pressure is increased to 60.0 KPa?
1 Answer
May 11, 2017
The volume is
Explanation:
We apply Boyle's Law at constant temperature and constant number of
P1V1=P2V2
The initial pressure is
The initial volume is
The final pressure is
The final volume is
V2=P1P2⋅V1
=4060⋅12.3=8.2u