Question

A gas occupies 2.23 L at 3.33 atm. What is the volume at 2.97 atm?

Answer 1

`P_1V_1=P_2V_2`. `V_2=2.50*L`

Explanation:

Given a quantity of gas, `P_1V_1=P_2V_2`. This is old Boyle's Law.

`V_2=(P_1V_1)/V_2=(2.23*Lxx3.33*atm)/(2.97*atm)=2.50*L`.

The utility of using these old empirical laws is that as long as we keep our units consistent we can quote volumes in litres or even pints, and pressures in atmospheres or foot pounds - and I presume old Boyle did so.