A gas occupies 2.23 L at 3.33 atm. What is the volume at 2.97 atm?

1 Answer
anor277
May 20, 2017

P_1V_1=P_2V_2P1V1=P2V2. V_2=2.50*LV2=2.50⋅L

Explanation:

Given a quantity of gas, P_1V_1=P_2V_2P1V1=P2V2. This is old Boyle's Law.

V_2=(P_1V_1)/V_2=(2.23*Lxx3.33*atm)/(2.97*atm)=2.50*LV2=P1V1V2=2.23⋅L×3.33⋅atm2.97⋅atm=2.50⋅L.

The utility of using these old empirical laws is that as long as we keep our units consistent we can quote volumes in litres or even pints, and pressures in atmospheres or foot pounds - and I presume old Boyle did so.

Related questions
See all questions in Gas Laws
Impact of this question
6697 views around the world
You can reuse this answer
Creative Commons License