A gas with a volume of 3.00 x 10^23.00x102 mL at 150.0 degrees C is heated until its volume is 6.00 X 10^26.00X102 mL. What is the new temperature of the gas if the pressure remains constant during the heating process?

1 Answer
Jun 4, 2017

We use old Charles' Law, VpropTVT; units of "absolute temperature"absolute temperature must be used, 00 ""^@C=273.15*KC=273.15K.

Explanation:

We use old Charles' Law, which states that at constant pressure, and a given quantity of gas, volume varies with temperature.........i.e. VpropTVT.

And thus V=kTV=kT. And if we solve for kk, we gets the relationship....

V_1/T_1=V_2/T_2V1T1=V2T2 for a given quantity of gas.......

T_2=(V_2xxT_1)/V_1T2=V2×T1V1, "absolute temperature"absolute temperature is used......

=(600*mLxx423.15*K)/(300*mL)=846.3*K=600mL×423.15K300mL=846.3K. Can you convert this temperature to ""^@CC?